Differentiating an Integral with Variable Limits (Leibniz Rule Explained Step-by-Step)
- Tyler Buffone

- Dec 9, 2024
- 1 min read
Updated: Oct 9

Example
Consider the following function:
![Mathematical equation on a dark background: F(x) = ∫ [(x²+1)/(2+cosx)] (1/t) dt. White handwritten text in a neat style.](https://static.wixstatic.com/media/cc5ac4_36e993d3144149bca16fa30095f0782d~mv2.png/v1/fill/w_793,h_177,al_c,q_85,enc_avif,quality_auto/cc5ac4_36e993d3144149bca16fa30095f0782d~mv2.png)
Find its derivative.
Solution
Use the Leibniz Integral rule:
![Mathematical equation on a dark background reads: "If F(x) = ∫[a(x) to b(x)] F(t)dt, then F'(x) = F(b(x))b'(x) - F(a(x))a'(x)."](https://static.wixstatic.com/media/cc5ac4_cb388514156340b29ca07319718d505a~mv2.png/v1/fill/w_980,h_186,al_c,q_85,usm_0.66_1.00_0.01,enc_avif,quality_auto/cc5ac4_cb388514156340b29ca07319718d505a~mv2.png)
Remark: this is also known as the Differentiation Under the Integral Sign Formula.
In this case:
f(t) = (1 / t), a(x) = 2 + cos(x), and b(x) = x² + 1.
So:
f(a(x)) = (1 / (2 + cos(x))
a'(x) = -sin(x)
f(b(x)) = (1 / (x² + 1))
b'(x) = 2x
Hence, the derivative of F(x) is:

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